December 22nd, 2009

LOG PROBLEM

What is the perimeter and area of rectangle that has a length of 2.34 mm and a width of 4.2 mm?

WORK TODAY

We logged onto a website today where we could calculate the perimeter and area of rectangles. Here is a link:http://www.bgfl.org/bgfl/custom/resources_ftp/client_ftp/ks2/maths/perimeter_and_area/index.html

HOMEWORK

What is the perimeter and the area of a rectangle with a length of 2.3 cm and a width of 9.2 cm?
MAKE SURE YOU SHOW FORMULA WORK!

December 18th, 2009

LOG PROBLEM

Solve for x:

20 = 2 + 3x

December 17th, 2009

LOG PROBLEM
What is the width of a rectangle that has a perimeter of 10 meters and a length of 3 meters?

WORK TODAY
Activity: We will measure the perimeter of our log books.

HOMEWORK
Perimeter Problems:
1. p = 25 cm, l = 4 cm, w = ?
2. p = 52 cm, l = 12 cm, w = ?
3. p = 300 cm, l = 60 cm, w = ?
4. p = 75 cm, l = 35 cm, w = ?
5. p = 5 cm, l = 1 cm, w = ?

December 16th

WORK TODAY
Quiz today on the distributive property and calculating perimeter.

HOMEWORK
Complete the worksheet handed out in class today.

December 15th, 2009

LOG PROBLEM

Simplify the following expression:
-2(9x-3) - 4(7x-8) -2

December 14th Problem Solutions:

1: 4(3x + 6) + 4(4x + 4)
12x +24 +16x +16
28x +40

2: 2(6x + 3) + 6(9x + 8)
12x + 6 + 54x +48
66x + 64

3: 3(9x + 5) + 5(5x + 6)
27x + 15 +25x +30
52x + 45

4: 9(8x + 5) + 4(7x + 7)
72x + 45 +28x + 28
100x + 73

5: 2(3x + 9) + 3(7x + 1)
6x + 18 + 21x +3
27x + 21

7: 5(5x + 2) + 7(9x + 1)
25x + 10 + 63x +7
88x + 17

8: 6(3x + 1) + 2(7x + 5)
18x + 6 + 14x +10
32x +16

December 14th Homework Solutions
1: -5(3x + 6) - 4(4x + 4)
-15x – 30 -16x -16
-31x -46

2: -6(6x + 3) - 6(9x + 8)
-36x -18 – 54x -48
-90x – 66

3: -4(9x + 5) - 5(5x + 6)
-36x – 20 -25x -30
-61x -50

4: -3(8x + 5) - 4(7x + 7)
-24x -15 -28x -28
-52x – 43

5: -8(3x + 9) - 3(7x + 1)
-24x – 72 -21x -3
-45x -75

CLASSWORK
1: -5(8x-3) - 3(7x-9) -8
2: 5(4x-12) - 3(9x-7) + 2
3: 9 (2x+ 8) + 2(-3x - 9) +12

HOMEWORK
Study for quiz on the distributive property and perimeter.

December 14th, 2009

LOG PROBLEM
What is the length of a rectangle that has a perimeter of 15.5 cm and a width of 3.4 cm?

Solution
P=2(l+w)
15.5cm = 2(l + 3.4cm)
15.5cm = 2l + 6.8cm
8.7cm = 2l
4.35cm = l

WORK TODAY
I passed back the quizzes dealing with the Distributive Property and combining like terms.
We also solved the following problems:
1: 4(3x + 6) + 4(4x + 4)
2: 2(6x + 3) + 6(9x + 8)
3: 3(9x + 5) + 5(5x + 6)
4: 9(8x + 5) + 4(7x + 7)
5: 2(3x + 9) + 3(7x + 1)
7: 5(5x + 2) + 7(9x + 1)
8: 6(3x + 1) + 2(7x + 5)
9: 7(6x + 3) + 3(9x + 1)
10: 9(2x + 2) + 8(4x + 9)
11: 8(7x + 1) + 2(7x + 4)
12: 7(3x + 9) - 9(9x + 8)
13: 9(6x + 1) - 2(6x + 7)
14: 6(3x + 3) - 8(5x + 3)
15: 8(4x + 3) - 2(2x + 6)

HOMEWORK
1: -5(3x + 6) - 4(4x + 4)
2: -6(6x + 3) - 6(9x + 8)
3: -4(9x + 5) - 5(5x + 6)
4: -3(8x + 5) - 4(7x + 7)
5: -8(3x + 9) - 3(7x + 1)

Solutions to first two problems:

1: -5(3x + 6) - 4(4x + 4)
-15x -30 -16x -16
-31x - 46

2: -6(6x + 3) - 6(9x + 8)
-36x - 18 -54x -48
-90x - 66

December 10th, 2009

LOG PROBLEM

What is the length of a rectangle that has a perimeter of 14.6 cm and a width of 3.2 cm?

Solution:
P=2(l+w)
14.6cm = 2(l + 3.2cm)

14.6cm = 2l + 6.4cm
-6.4cm -6.4cm

8.2cm = 2l
/2 /2

4.1cm = l

HOMEWORK
1. P = 12.1 m, w = 2.5 m, l =?
2. P = 7 in, w = 1.5in, l =?
3. P = 125 cm, w = 20 cm, l =?
4. P = 40 m, w = 18 m, l =?

December 9th, 2009

LOG PROBLEM
What is the perimeter of a rectangle that has a width of 4 meters and a length of 8 meters?
SHOW FORMULA WORK!

Solution:
P = 2 (l +w)
P = 2 (8m + 4m)
P = 2(12m)
P = 24m

WORK TODAY
We went over the Math Benchmark results today. Great job 706 and 707! We also calculated the width of a rectangle after being given the perimeter and the length of the rectangle.

Here is a sample problem:
What is the width of a rectangle if the perimeter is 10 cm and the length is 2 cm?
P = 2 (l+w)
10cm = 2 (2cm + w)
10cm = 4cm + 2w

10cm = 4cm + 2w
-4cm -4cm


6cm = 2w
/2 /2

3cm = w

HOMEWORK
Complete the following perimeter problems after being the perimeter and length:
1. p = 30 cm, l = 6 cm, w = ?
2. p = 12 cm, l = 2 cm, w = ?
3. p = 200 cm, l = 40 cm, w = ?
4. p = 45 cm, l = 15 cm, w = ?
5. p = 6 cm, l = 2 cm, w = ?
6. p = 50 cm, l = 10 cm, w = ?
7. p = 8 m, l = 2 m, w = ?

December 8th, 2009

LOG PROBLEM
Evaluate the following expression:
2n – 3(5n +9)

Solution:
2n -15n -27
-13n - 27

WORK TODAY
We did a few more problems dealing with the Distributive Property. We then discussed the formula for Perimeter of a Rectangle and copied it. The class then measured the length and width of their desks and binders. They used those measurements and the formula to calculate Perimeter.

Formula for Perimeter of a Rectangle: Perimeter = 2 (length + width)

Example problem:
Show formula work for a rectangle with a width of 10 cm and a length of 15 cm
P = 2 (l +w)
P = 2 (10 cm + 15 cm)
P = 2 (25 cm)
P = 50 cm

HOMEWORK

Show formula work for calculating the perimeter of the following rectangles:
1.) l = 2 cm, w = 4 cm
2.) l = 4 cm, w = 6 cm
3.) l = 6cm, w = 8 cm

December 7th, 2009

LOG PROBLEMS
Simplify these expressions.
1.) 17 - 4(3x -2)
2.) 3x -2(3x +1)

Solutions:
1.) 17 - 12x +8 = 25 - 12x
2.) 3x - 6x -2 = -3x - 2

WORK TODAY
We continued our work dealing with the Distributive Property today.

HOMEWORK
Complete the rest of the problems that we worked on today. This work counts as a QUIZ!

Solutions to Worksheet 2:
1. 34n+ 30
2. -55x+ 21
3. 33n- 7
4. -3 - 6n
5. -7 - 6x
6. -44n+ 25
7. 23 + 40x
8. -8x
9. 23 + 40x
10. 59x+ 49

Solutions to Worksheet 3:
1. 29x - 18
2. 6n+ 40
3. -34x+ 72
4. 8x - 36
5. x - 15
6. -15n - 35
7. 80 - 20 x
8. 18 - 14n
9. -10x+ 10
10. -50

December 3rd, 2009

LOG PROBLEM
Simplify this expression.
2(3y-4)

Solution:
2(3y) - (2)(4)
6y - 8

WORK TODAY

We continued our work dealing with the Distributive Property.

HOMEWORK

Complete the following problems:
1.) −n−5(−6 − 7n)
2.) −7(8x− 3) +x
3.) 7(5n− 1) − 2n
4.) 3 −6(1 +n)
5.) −(4 + 6x) − 3
6.) 5(−8n+ 5) − 4n

Solutions to first 3 problems:
1.) 34n +30
2.) -55x +21
3.) 33n - 7

December 2nd, 2009

LOG PROBLEM

Simplify the following expression:
3 + 4 (y -5)

Answer:
3 + 4 (y -5)
3 + 4y -20
4y -17 OR -17 +4y

WORK TODAY

We worked on simplifying expressions by use of the Distributive Property of Multiplication over Addition.

706 HOMEWORK

Simplify the following expressions:
1) 3(9x-7)
2) 8(3n+2)
3) 4(3h - 2)

707 HOMEWORK

Complete the problems posted on December 1st for 706.

December 1st, 2009

LOG PROBLEM
Show formula work for calculating the area of your desk. The width is 62.1 cm and the length is 46.8 cm.

ANSWER
Area = length x width
A = lw
A =46.8cm x 62.1cm
A = 2906.28 centimeters squared

WORK TODAY
We worked on the distributive property. The distributive property is the idea that a factor can be distributed (spread) to two addends.
For example: 2 × (1 + 3) = (2 × 1) + (2 × 3).

HOMEWORK for 706
1.) 3 −3(x− 2)
2.) −(1 − 5n) − 7n
3.) 8 +7(7n− 4)
4.) 4x+5(3x− 3)
5.) 5 −2(8x+ 4)

HOMEWORK for 707

Complete problems 12-17 on the worksheet handed out in class today.