12/9/09

December 9th, 2009

LOG PROBLEM
What is the perimeter of a rectangle that has a width of 4 meters and a length of 8 meters?
SHOW FORMULA WORK!

Solution:
P = 2 (l +w)
P = 2 (8m + 4m)
P = 2(12m)
P = 24m

WORK TODAY
We went over the Math Benchmark results today. Great job 706 and 707! We also calculated the width of a rectangle after being given the perimeter and the length of the rectangle.

Here is a sample problem:
What is the width of a rectangle if the perimeter is 10 cm and the length is 2 cm?
P = 2 (l+w)
10cm = 2 (2cm + w)
10cm = 4cm + 2w

10cm = 4cm + 2w
-4cm -4cm


6cm = 2w
/2 /2

3cm = w

HOMEWORK
Complete the following perimeter problems after being the perimeter and length:
1. p = 30 cm, l = 6 cm, w = ?
2. p = 12 cm, l = 2 cm, w = ?
3. p = 200 cm, l = 40 cm, w = ?
4. p = 45 cm, l = 15 cm, w = ?
5. p = 6 cm, l = 2 cm, w = ?
6. p = 50 cm, l = 10 cm, w = ?
7. p = 8 m, l = 2 m, w = ?